The singular locus of a reduced subspace contains no smooth hypersurface #
For a reduced closed analytic subspace Y with ideal sheaf I, the singular locus
Sing(Y) = Y โ Reg(Y) contains no nonempty closed smooth hypersurface H
(IdealSheaf.not_subset_sing_of_isClosedSubmanifold_one), and no nonempty open set
(IdealSheaf.not_subset_sing_of_isOpen). The hypersurface statement: at every point q of H
the stalk I_q lies in the ideal (h) of H, h an adapted coordinate (every germ of I
vanishes on Y โ H), and h โ I_q, since otherwise I_q = (h) and ๐ช_q/I_q would be regular,
against q โ Sing(Y). So the saturation (I : I_H^โ) (IdealSheaf.saturation) is a proper ideal
at every point of H, hence its stalk at a โ H also lies in (h). For f โ I_a this gives
f โ (hยฒ), and then f โ (h^m) for every m by induction, since I_a is radical: from
f = h^m g, (hg)^m = f g^{mโ1} โ I_a, so hg โ I_a โ (hยฒ) and g โ (h), the stalk being a
domain. Krull's intersection theorem (Ideal.iInf_pow_eq_bot_of_isLocalRing) then gives
f = 0, so I_a = 0 and ๐ช_a/I_a = ๐ช_a is regular, against a โ Sing(Y). The open-set
statement: a germ of I_a vanishing on a neighbourhood of a is zero, so I_a = 0.
These are the facts behind Wลodarczyk's remark that the centres of the embedded
desingularization have codimension at least two [Wlo09, Remark (2) after Theorem 2.0.3]: a centre
of codimension at most one lies over Sing(Y), so it meets the exceptional divisor everywhere
(Hironaka/Resolution/Analytic/Wlo09/CenterCodim.lean). The arguments are not in the sources.
The singular locus of a reduced subspace contains no nonempty closed smooth hypersurface.
The singular locus of a subspace contains no nonempty open set: a germ vanishing on a
neighbourhood is zero, so the stalk of I at a point of the open set is zero and the quotient
is regular.