Stalks of a closed subscheme through an isomorphism of the ambient stalks #
"Since Z_j is smooth, g is not an isomorphism over any point of Sing X̄"
[Kol07, Theorem 27, proof]; read backwards, this gives the clause of [Kol07, Theorem 36 (3)] that
the resolution is an isomorphism exactly over the smooth locus: at a point p of the end result
X_j ⊆ A_j over which the ambient sequence is a local isomorphism
(Hironaka/Resolution/Algebraic/Kol07/OffCenters.lean), the local ring of X_j at p is the local
ring of X at g(p), so X is smooth at g(p) because X_j is. The transport is a chain of ring
isomorphisms: the stalk of a closed subscheme is the quotient of the ambient stalk by the stalk of
its ideal (the first isomorphism theorem, the stalk map being surjective with kernel that stalk,
ker_stalkMap_of_isClosedImmersion), the ambient stalks are isomorphic, and the isomorphism
carries one ideal onto the other (Ideal.quotientEquiv).
stalkEquivQuotient_of_isClosedImmersion:𝒪_{Y,y} ≃ 𝒪_{X,g y} / (ker g)_{g y}.isRegularLocalRing_stalk_of_isIso_stalkMap_of_stalkIdeal_eq: for two closed immersionsg : Y ⟶ X,g' : Y' ⟶ X', a morphismf : X' ⟶ Xand pointsp : Y',y : Ywithf (g' p) = g y,fan isomorphism on stalks atg' pcarrying(ker g)_{f (g' p)}onto(ker g')_{g' p}, the local ring ofYatyis regular when that ofY'atpis.
The schemes are arbitrary.
The stalk of the source of a closed immersion g at y is the quotient of the stalk of the
target at g y by the stalk of ker g (the first isomorphism theorem for the surjective stalk
map, ker_stalkMap_of_isClosedImmersion).
Equations
Instances For
For closed immersions g : Y ⟶ X, g' : Y' ⟶ X', a morphism f : X' ⟶ X and points p : Y',
y : Y with f (g' p) = g y, if f is an isomorphism on stalks at g' p carrying the stalk of
ker g onto the stalk of ker g', then the local ring of Y at y is regular whenever the
local ring of Y' at p is:
𝒪_{Y',p} ≃ 𝒪_{X',g' p}/(ker g') ≃ 𝒪_{X,f (g' p)}/(ker g) ≃ 𝒪_{X,g y}/(ker g) ≃ 𝒪_{Y,y}. Not in
the sources in this form; it is the transport behind [Kol07, Theorem 27, proof] read backwards.