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Hironaka.Scheme.BlowUpSequence.ClosedImmersionStalk

Stalks of a closed subscheme through an isomorphism of the ambient stalks #

"Since Z_j is smooth, g is not an isomorphism over any point of Sing X̄" [Kol07, Theorem 27, proof]; read backwards, this gives the clause of [Kol07, Theorem 36 (3)] that the resolution is an isomorphism exactly over the smooth locus: at a point p of the end result X_j ⊆ A_j over which the ambient sequence is a local isomorphism (Hironaka/Resolution/Algebraic/Kol07/OffCenters.lean), the local ring of X_j at p is the local ring of X at g(p), so X is smooth at g(p) because X_j is. The transport is a chain of ring isomorphisms: the stalk of a closed subscheme is the quotient of the ambient stalk by the stalk of its ideal (the first isomorphism theorem, the stalk map being surjective with kernel that stalk, ker_stalkMap_of_isClosedImmersion), the ambient stalks are isomorphic, and the isomorphism carries one ideal onto the other (Ideal.quotientEquiv).

The schemes are arbitrary.

noncomputable def AlgebraicGeometry.stalkEquivQuotient_of_isClosedImmersion {X Y : Scheme} (g : Y ⟶ X) [IsClosedImmersion g] (y : ↥Y) :
↑(X.presheaf.stalk (g y)) ⧸ (Scheme.Hom.ker g).stalkIdeal (g y) ≃+* ↑(Y.presheaf.stalk y)

The stalk of the source of a closed immersion g at y is the quotient of the stalk of the target at g y by the stalk of ker g (the first isomorphism theorem for the surjective stalk map, ker_stalkMap_of_isClosedImmersion).

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Instances For
    theorem AlgebraicGeometry.isRegularLocalRing_stalk_of_isIso_stalkMap_of_stalkIdeal_eq {X Y X' Y' : Scheme} (g : Y ⟶ X) [IsClosedImmersion g] (g' : Y' ⟶ X') [IsClosedImmersion g'] (f : X' ⟶ X) {p : ↥Y'} {y : ↥Y} (hpt : f (g' p) = g y) [CategoryTheory.IsIso (Scheme.Hom.stalkMap f (g' p))] (h2 : (Scheme.Hom.ker g').stalkIdeal (g' p) = Ideal.map (CommRingCat.Hom.hom (Scheme.Hom.stalkMap f (g' p))) ((Scheme.Hom.ker g).stalkIdeal (f (g' p)))) [IsRegularLocalRing ↑(Y'.presheaf.stalk p)] :

    For closed immersions g : Y ⟶ X, g' : Y' ⟶ X', a morphism f : X' ⟶ X and points p : Y', y : Y with f (g' p) = g y, if f is an isomorphism on stalks at g' p carrying the stalk of ker g onto the stalk of ker g', then the local ring of Y at y is regular whenever the local ring of Y' at p is: 𝒪_{Y',p} ≃ 𝒪_{X',g' p}/(ker g') ≃ 𝒪_{X,f (g' p)}/(ker g) ≃ 𝒪_{X,g y}/(ker g) ≃ 𝒪_{Y,y}. Not in the sources in this form; it is the transport behind [Kol07, Theorem 27, proof] read backwards.